(1/3)^k=9

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Solution for (1/3)^k=9 equation: 



(1/3)^k=9

We move all terms to the left:

(1/3)^k-(9)=0



Domain of the equation: 3)^k!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

(+1/3)^k-9=0

We multiply all the terms by the denominator


(+1-9*3)^k=0

We add all the numbers together, and all the variables

(-26)^k=0

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